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Geometry and Trigonometry / Area and volume Difficulty: Easy

Triangle R has an area of $80 square centimeters left parenthesis cm squared right parenthesis$ . Square S has side lengths of $4 cm$ . What is the total area of triangle R and square S, $in {cm}^{2}$ ?

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Explanation

Choice D is correct. It’s given that triangle R has an area of $80$ ${cm}^{2}$ . The area of a square is $l^{2}$ , where $l$ is the side length of the square. It's given that square S has side lengths of $4$ $cm$ . It follows that the area, in ${cm}^{2}$ , of square S is $4 squared$ , or $16$ . Therefore, the total area, in ${cm}^{2}$ , of triangle R and square S is $80 plus 16$ , or $96$ .

Choice A is incorrect and may result from conceptual or calculation errors.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.